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daveE
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| pic16f88 adc bug?? |
 Posted: Sun May 28, 2006 12:27 pm |
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| Code: | #include <16F88.h>
#device adc=8
#fuses XT,NOWDT,PROTECT,NOBROWNOUT,PUT,MCLR
#use delay (clock=4000000)
#use rs232(baud=9600, xmit=PIN_B5, rcv=PIN_B2)
//int16 result;
main()
{
setup_adc( ADC_CLOCK_DIV_4);
setup_adc_ports(sAN0|VSS_VDD);
set_adc_channel(sAN0);
while(1)
{
delay_ms(500);
// result = read_adc();
printf("TEST: %x",read_adc());
output_high(PIN_B4);
delay_ms(500);
output_low(PIN_B4);
delay_ms(500);
}
} |
The ADC won't work if ur analog signal is inputted to pin 17/ AN0 but it will work if u use pin 18/AN1. weird. Seems like the adc channel are shifted up one port. If u put A0, its actually A1.
here's what in the pic16F88.h for adc section.
#define sAN0 1 //| A0
#define sAN1 2 //| A1
#define sAN2 4 //| A2
#define sAN3 8 //| A3
#define sAN4 16 //| A4
#define sAN5 32 //| B6
#define sAN6 64 //| B7
#define NO_ANALOGS 0 // None
Is there something with the way i declare the ADC or is this a bug?? I'm using v3.202 |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Sun May 28, 2006 2:43 pm |
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| Quote: | set_adc_channel(sAN0);
Seems like the adc channel are shifted up one port. If u put A0, its actually A1. |
Here is what the CCS manual says about the parameters that
can be used with the set_adc_channel() function:
| Quote: | set_adc_channel (chan)
chan is the channel number to select. Channel numbers start at 0.
Examples:
set_adc_channel(2); |
Compare your parameters with the ones that the manual says to use. |
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