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Exit from long loop with interrupt?

 
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TekTrixter



Joined: 10 Apr 2006
Posts: 3
Location: North Carolina, USA

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Exit from long loop with interrupt?
PostPosted: Mon Apr 10, 2006 5:40 pm     Reply with quote

Currently the program starts / stops the blinking pattern of the LEDs attached to the output pins. However, as written it can't stop within the loop, only between loops. How can I cause the loop to end after the interrupt? I know that I could set a flag in the interrupt and then check it between LED changes, but that doesn't seem to be an elegant method.

Code:

#include "D:\Data files\robot\BlinkLED\BlinkLED.h"

void setup();


boolean btnToggle = false;

#int_EXT
void EXT_isr() {
   output_low(PIN_A2);   // indicate that program is within ISR
   disable_interrupts(GLOBAL);
   if (btnToggle){
      btnToggle = false;
   }else{
      btnToggle = true;
   }
   delay_ms(50);
   clear_interrupt(INT_EXT);
   enable_interrupts(GLOBAL);
   output_high(PIN_A2);
}



void main() {
   setup();

   while(true){
      if(btnToggle){                         //change LED pattern
         output_toggle(PIN_B3);
         delay_ms(500);

         output_toggle(PIN_B3);
         output_toggle(PIN_B2);
         delay_ms(500);

         output_toggle(PIN_B2);
         output_toggle(PIN_B1);
         delay_ms(500);

         output_toggle(PIN_B1);
         output_toggle(PIN_B5);
         delay_ms(500);

         output_toggle(PIN_B5);
         delay_ms(500);
      }
   }
}

void setup(){
   setup_timer_0(RTCC_INTERNAL|RTCC_DIV_1);
   setup_timer_1(T1_DISABLED);
   setup_timer_2(T2_DISABLED,0,1);
   setup_comparator(NC_NC_NC_NC);
   setup_vref(VREF_LOW|-2);
   ext_int_edge(H_TO_L);
   enable_interrupts(INT_EXT);
   enable_interrupts(GLOBAL);
   setup_oscillator(OSC_4MHZ);

   output_float(PIN_B0);
   output_high(PIN_B3);
   output_high(PIN_B2);
   output_high(PIN_B1);
   output_high(PIN_B5);
   output_high(PIN_A2);
}
kender



Joined: 09 Aug 2004
Posts: 768
Location: Silicon Valley

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PostPosted: Mon Apr 10, 2006 8:00 pm     Reply with quote

Add more places where you test the flag, which you set in the ISR. For example:

Code:

while(true){
      if(btnToggle) goto endloop;                         //change LED pattern

      output_toggle(PIN_B3);
      delay_ms(500);

      if(btnToggle) goto endloop;

      output_toggle(PIN_B3);
      output_toggle(PIN_B2);
      delay_ms(500);

      if(btnToggle) goto endloop;

      output_toggle(PIN_B2);
      output_toggle(PIN_B1);
      delay_ms(500);

      if(btnToggle) goto endloop;

      output_toggle(PIN_B1);
      output_toggle(PIN_B5);
      delay_ms(500);

      if(btnToggle) goto endloop;

      output_toggle(PIN_B5);
      delay_ms(500);

// or you can also split up your delay routines like this
// instead of delay_ms(500);
for (i = 0; i < 5; ++i)
{
     delay_ms(100);
     if(btnToggle) goto endloop;
}

endloop:
}
asmallri



Joined: 12 Aug 2004
Posts: 1634
Location: Perth, Australia

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Re: Exit from long loop with interrupt?
PostPosted: Mon Apr 10, 2006 11:03 pm     Reply with quote

TekTrixter wrote:
Currently the program starts / stops the blinking pattern of the LEDs attached to the output pins. However, as written it can't stop within the loop, only between loops. How can I cause the loop to end after the interrupt? I know that I could set a flag in the interrupt and then check it between LED changes, but that doesn't seem to be an elegant method.


Using a flag is in the interrupt handler is elegant. I suggest the following:

    get rid of the disable interrupts in the interrupt handler unless there are other interrupt sources that you specifically want disabled.
    get rid of the enable_interrupts(global) in your interrupt handler - it is a sure way to crash the PIC.
    get rid of the clear_interrupt(INT_EXT) from the interrupt handler . It is not required the compiler does it automatically for you.
    get rid of the delay_ms from the interrupt handler. By putting this in the handler the compiler will add a disable interrupts into the mainline code whenever delay_ms is invoked which means you may lose interrupts.

    A method I use is to enable a timer in the interrupt handler - in your case one with 50ms timeout. You can then sit in the handler until the timeout expires - alternatively (the method I use) you can return immediately from the handler and in the mainline you can test if the timer is running (means an interrupt has occured and you are waiting for a timeout) then loop until the timer IF is set. You can then stop the timer, clear the flag and clear the output.

    Alternatively (or in addition) use a timer instead of delay_ms() in the mainline. In this case you would clear the TF flag and start the timer. You you then sit in a while loop such as

    Code:

         Ext_Intr_Processed_by_handler = false;
         while (!Some_Timer_TF & !Ext_Intr_Processed_by_handler)
                  // do nothing
                 ;
           // here if the timer expired or an interrupt was processed
           // do something else ....

_________________
Regards, Andrew

http://www.brushelectronics.com/software
Home of Ethernet, SD card and Encrypted Serial Bootloaders for PICs!!


Last edited by asmallri on Tue Apr 11, 2006 5:55 pm; edited 2 times in total
Humberto



Joined: 08 Sep 2003
Posts: 1215
Location: Buenos Aires, La Reina del Plata

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PostPosted: Tue Apr 11, 2006 7:33 am     Reply with quote

Code:


//----------------------------------
#INT_EXT
void EXT_isr()
{
   if( btnToggle)
     { btnToggle = false; }
   else
     { btnToggle = true;  }
}

//-----------------------------------
void my_wait_loop(int times)
{   
   do
     {
      delay_ms(10);
     }while((--times) && (btnToggle));
}
//-----------------------------------

In main replace delay_ms(500) for my_wait_loop(n);
Code:

         output_toggle(PIN_B3);
         output_toggle(PIN_B2);
         my_wait_loop(50);

         output_toggle(PIN_B2);
         output_toggle(PIN_B1);
         my_wait_loop(50);
 



Humberto
Mark



Joined: 07 Sep 2003
Posts: 2838
Location: Atlanta, GA

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PostPosted: Tue Apr 11, 2006 8:58 am     Reply with quote

Just to add upon what's already been posted
Code:

void my_wait_loop(int times)
{   
   do
     {
      delay_ms(10);
     }while((--times) && (btnToggle));
}

void main()
{
  int state;
  setup();

  while(true)
  {
    state = 0;
    while (btnToggle)
    {
      switch (state)
      {
        case 0:
          output_toggle(PIN_B3);
          break;
        case 1:
          output_toggle(PIN_B3);
          output_toggle(PIN_B2);
          break;
        case 3:
          output_toggle(PIN_B2);
          output_toggle(PIN_B1);
          break;
        case 4:
          output_toggle(PIN_B1);
          output_toggle(PIN_B5);
          break;
        case 5:
          output_toggle(PIN_B5);
          break;
        case 6:
          state = 0;
          continue;
      }
      state++
      my_wait_loop(50);
    }
  }
}
TekTrixter



Joined: 10 Apr 2006
Posts: 3
Location: North Carolina, USA

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PostPosted: Wed Apr 19, 2006 10:26 am     Reply with quote

Thank you to everyone that replied. Mark's suggestion of a CASE is what I was origionally looking for (it avoids cut and pasting code). I also needed the interruptable delay as well (and didn't even know it!). I'd like to specificly thank asmallri for the list of corrections and hints.

I'm now working on a function for an interruptable delay using a timer interrupt and a break_delay flag.

Again, thank you to everyone that helped out.
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