What does this code mean?

[Sophi]

I'm looking at CCS's LT1298 code, specifically the line:

if((data_byte & 1)==0)

What does this mean and how does it work? I've copied the entire segment below.
Thanks!
Sophi

void write_adc_byte(byte data_byte, byte number_of_bits) {
byte i ;
delay_cycles(1); // was 2 us
for(i=0; i<number_of_bits; ++i) {
if((data_byte & 1)==0)
output_low(ADC_DIN);
else
output_high(ADC_DIN);
data_byte=data_byte>>1;
output_high(ADC_CLK);
delay_cycles(1); // was 50 uS
output_low(ADC_CLK);
delay_cycles(1); // was 50 uS
}

[valemike]

if((data_byte & 1)==0)

data_byte is an 8-bit value.
You 'and' it with 1, which is the same as and'ing it with '0000 0001'

Thus if the LSB (bit 0) is a 0, then your if-statement is TRUE.

Another way to write it would be:

if (!(data_byte & 0x01))

in assembly, it would be:
btfsc databyte, 0