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how do I use the return of (-1)

 
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mike holeton
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how do I use the return of (-1)
PostPosted: Tue May 10, 2005 9:39 pm     Reply with quote

example code

char CompareName( char *OtherName )
{
char i;

for (i = 0; (i<J1939_DATA_LENGTH) && (OtherName[i] == CA_Name[i]); i++);

if (i == J1939_DATA_LENGTH)
return 0;
else if (CA_Name[i] < OtherName[i] )
return -1; //how do I do this?
else
return 1;
Ttelmah
Guest







PostPosted: Wed May 11, 2005 3:13 am     Reply with quote

Key thing. A value has to be 'signed', to return a negative number. As written, a program at the other 'end', will 'see' 255'. A 'char' (and an integer), in CCS C, default to unsigned data types.
Basically, '-1', is coded in binary, as '11111111'. A character is an unsigned value, so the subroutine will return 255 (which is what the same binary value gives when treated as an unsigned number).
If you want to return a -1 'error' status, you have to change the declaration of the function, to:
signed char CompareName( char *OtherName )

Remember though that with a 'signed' declaration, the maximum value that can be returned, drops to 127.

Best Wishes
Paolino



Joined: 19 Jan 2004
Posts: 42

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PostPosted: Wed May 11, 2005 3:14 am     Reply with quote

I have understood this: the statment
Code:

return -1;

has no effect in your code. Is it correct? If so, you have to declare differently the function and the variable returned. Infact, directly from CCS help on line
Quote:

All types, except float, by default are unsigned; however, maybe preceded by unsigned or signed


Try this:
Code:

signed char CompareName( char *OtherName )
{
   char i;

   for (i = 0; (i<J1939_DATA_LENGTH) && (OtherName[i] == CA_Name[i]); i++);

   if (i == J1939_DATA_LENGTH)
   return 0;
   else if (CA_Name[i] < OtherName[i] )
   return -1; //Now it should work
   else
   return 1;
}
 
 


If you prefer to keep the funciotn as is, you have to return a positive value, instead of -1.
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