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8 bit unsigned vs signed

 
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DarkKobold



Joined: 21 Jan 2004
Posts: 4

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8 bit unsigned vs signed
PostPosted: Wed Jan 21, 2004 9:56 pm     Reply with quote

Hi all.
I believe that by using the char identifier, I can use it as an unsigned 8 bit integer. (I may be wrong). I am trying to use it for time, a total of 3 minutes, which is 180 seconds. (obviously) However, if I use an algorithm to decode the individual numbers, such as
min = 0;
tensec = 0;
//get x
if ((x - 60) > 0)
{
x -= 60;
min++;
}
if ((x - 10) > 0)
{
tensec++;
}
sec = x;

will the negation require it to convert to 16 bit math, therefore requiring more overhead?
dvsoft



Joined: 28 Nov 2003
Posts: 46

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PostPosted: Thu Jan 22, 2004 2:04 am     Reply with quote

Bonjour

int8 Value,Minute,Seconde;

Value = getc();
Minute = Value / 60;
Seconde = Value % 60;

Bonne journée
Mark



Joined: 07 Sep 2003
Posts: 2838
Location: Atlanta, GA

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PostPosted: Thu Jan 22, 2004 7:06 am     Reply with quote

There is a little problem with your routine. You should use a loop:
Code:

min = 0;
tensec = 0;
//get x
while (x >= 60)
{
  x -= 60;
  min++;
}
while (x >=  10)
{
  x -= 10;
  tensec++;
}
sec = x;

Neutone



Joined: 08 Sep 2003
Posts: 839
Location: Houston

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Re: 8 bit unsigned vs signed
PostPosted: Thu Jan 22, 2004 8:17 am     Reply with quote

DarkKobold wrote:

if ((x - 60) > 0)


This line can be a problem.

A better way to construct the syntax would be this.
Code:

if(x>60)

This avoids having an under flow without having to use signed math. The compiler will actually break the C statement into assembly, performs a subtraction and then test for an underflow to solve the IF. Subtracting 1 from 0 will result in 255 and an underflow when using an unsigned 8 bit integer. The test you wrote will only work for signed numbers.
DarkKobold



Joined: 21 Jan 2004
Posts: 4

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PostPosted: Thu Jan 22, 2004 3:30 pm     Reply with quote

Thank you for all of your help - I am still a tad confused. Will this guarentee to stay an 8 bit number? can you have an 8 bit number ranged 255-0 in PICC?
Mark



Joined: 07 Sep 2003
Posts: 2838
Location: Atlanta, GA

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PostPosted: Thu Jan 22, 2004 3:46 pm     Reply with quote

x-60 will always be greater than 0 unless x=60. The reason for this is since there is no sign bit, numbers cannot be < 0 only >= 0. If x=0 and you subtract 1 from it, x will now equal 255. Hope this clears it up for you.
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Thu Jan 22, 2004 3:48 pm     Reply with quote

Quote:
Will this guarantee to stay an 8 bit number?

The compiler will not change the data type. It will stay as
an unsigned char (ie., 8 bits, unsigned). The assembly
code generated by the compiler will be for 8-bit unsigned math.

Quote:
Can you have an 8 bit number ranged 255-0 in PICC?

Yes. Just use "char" as the data type.
In CCS, a "char" is the same an "unsigned char".
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