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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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 Posted: Mon Nov 26, 2007 1:53 am |
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Here is a test program for the LCD on the PicDem Mechatronics
Demonstration Board.
I don't have the Mechatronics board, so I can't test this program.
But I believe it has a good chance to work. I looked at the ASM
source code for the Mechatronics board. I've tried to make the
program below be similar to that ASM code, in terms of setting up
the LCD and by using the internal oscillator at 8 MHz.
I'm using the CCS lcd_symbol() function to turn on the three digits
on the right side of the LCD. I followed the method shown in the
CCS example file, Ex_LCD92.c. At this time, I don't have any code
to turn on the left-most '1' digit, or the decimal points, or any of the
special segments such as the diode or "low battery" segments.
| Code: | #include <16F917.H>
#fuses INTRC_IO, NOWDT, NOPROTECT, NOBROWNOUT, PUT
#use delay(clock=8000000)
// The LCD digits are numbered in the following way,
// according to the Varitronix VIM-332-DP data sheet.
// _ _ _
// | |_| |_| |_|
// | |_| |_| |_|
//
// Digit 4 3 2 1
//
// The CCS lcd_symbol() function will be used to display digits
// 1, 2, and 3. The following define statements tell the
// lcd_symbol() function which PIC pins are connected to the
// LCD segment pins.
// There is a table on page 58 of the PicDem Mechatronics
// Demonstration Board data sheet which lists the connections
// that are used to make these define statements.
//
// Digit segments A B C D E F G DP
// b7 b6 b5 b4 b3 b2 b1 b0
#define DIGIT3 COM0+3, COM0+11, COM2+11, COM3+3 , COM2+3, COM1+3, COM1+11, COM3+2
#define DIGIT2 COM0+6, COM0+21, COM2+21, COM3+6, COM2+6, COM1+6, COM1+21, COM3+11
#define DIGIT1 COM0+22, COM0+23, COM2+23, COM3+22, COM2+22, COM1+22, COM1+23, COM3+21
// The following array tells the CCS lcd_symbol() function which
// segments to turn on, to display the numbers from 0 to 9.
// 0 1 2 3 4 5 6 7 8 9
byte const Digit_Map[10] = {0xFC,0x60,0xDA,0xF2,0x66,0xB6,0xBE,0xE0,0xFE,0xE6};
#define BLANK 0 // For a blank digit, don't turn on any segments.
#byte LCDDATA6 = 0x116
#bit seg_4bc = LCDDATA6.2 // Controls left-most digit ("1")
int8 lcd_pos;
//-----------------------------------------------
void lcd_putc(char c)
{
int8 segments;
if(c == '\f')
{
lcd_pos = 0;
}
else
{
if((c >= '0') && (c <= '9'))
segments = Digit_Map[c - '0'];
else
segments = BLANK;
switch(lcd_pos)
{
case 1: // 1000's digit (left-most digit on lcd)
if(c == '1') // Is the top digit = 1 ?
seg_4bc = 1; // If so, display it
else // If it's not = 1, don't display it.
seg_4bc = 0;
break;
case 2: lcd_symbol(segments, DIGIT3); break; // 100's digit
case 3: lcd_symbol(segments, DIGIT2); break; // 10's digit
case 4: lcd_symbol(segments, DIGIT1); break; // 1's digit
}
}
lcd_pos++;
}
//===================================
void main()
{
int16 number;
setup_lcd(LCD_MUX14 | LCD_BIAS_PINS, 0);
number = 1234;
printf(lcd_putc,"\f%4lu",number); // Always send 4 digits
while(1);
} |
-------
Edit:
Updated the code so that it's the same as the code shown on page 2 of
this thread. The code above incorporates two bug fixes, and it adds the
ability to display the left-most digit.
Last edited by PCM programmer on Tue Sep 16, 2008 6:01 pm; edited 2 times in total |
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Sebastian20000
Joined: 09 Nov 2007
Posts: 12
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| Posted: Mon Nov 26, 2007 12:25 pm |
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Hi,
I test the program today and it works!
Thanks a lot.
One further question:
I don´t understand the line: c - '0' in the array:
| Code: | | segments = Digit_Map[c - '0']; |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Tue Nov 27, 2007 2:10 pm |
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| Quote: | I don´t understand the line: c - '0' in the array:
segments = Digit_Map[c - '0']; |
The lcd_putc() function expects to receive an ASCII number from 0 to 9
as the input value. ASCII numbers '0' to '9' have hex values of 0x30
to 0x39.
The code needs to use the input value as an index into the Digit_Map
array. But to do this, it must subtract off the ASCII "bias" of 0x30.
In other words, input values of 0x30 to 0x39 need to be converted to
values of 0x00 to 0x09. Then you can use it as an index into an
array which has 10 elements in it.
You could write the code to subtract the ASCII bias as
but it's very common for programmers to write it as
because it shows very clearly that you're working with ASCII characters,
and that the base value of your index is derived from the ASCII number '0'. |
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Guest
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| Help on LCD of Mechatronics Demo board |
| Posted: Fri Sep 12, 2008 9:32 am |
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I just copy and paste the code above and when I compile. The following error encounter.
| Quote: |
Executing: "C:\CCS_PIC\PCM\PICC\Ccsc.exe" "lcd.c" +FM +DF +LN +T -A +M +Z +Y=9 +EA
*** Error 12 "C:\PICC Experiment\Mechantronic\lcd.c" Line 69(23,36): Undefined identifier LCD_BIAS_PINS
1 Errors, 0 Warnings.
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Fri Sep 12, 2008 10:01 am |
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That constant is defined in all the 16F91x header files:
| Quote: |
c:\program files\picc\devices\16f913.h
#define LCD_BIAS_PINS 0x10
c:\program files\picc\devices\16f914.h
#define LCD_BIAS_PINS 0x10
c:\program files\picc\devices\16f916.h
#define LCD_BIAS_PINS 0x10
c:\program files\picc\devices\16f917.h
#define LCD_BIAS_PINS 0x10 |
If you don't have that #define statement, you're probably not using a
16F91x PIC. Or maybe you have a very old compiler version. |
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Guest
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| Posted: Fri Sep 12, 2008 10:13 am |
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How to put all 4 digits on to the LCD.
e.g.
I want to output ADC channel 0 to the LCD, the min result = 0, the max= 1023.
What should I add to the code to do that?
Also anyone know the actual manf. # of the LCD so I can look at the datasheet.
Thanks.. |
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dyeatman
Joined: 06 Sep 2003
Posts: 1933
Location: Norman, OK
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Guest
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| Posted: Fri Sep 12, 2008 11:48 am |
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| I have PCM Ver 3.249 |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Fri Sep 12, 2008 12:17 pm |
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In vs. 3.249 they didn't have the LCD_BIAS_PINS constant in the
16F917.H file. They added it later in vs. 4.xxx. All the rest of the
LCD constants in the .H file are the same in both versions.
Maybe during the weekend I'll look at it and see what's necessary
to add support for the 1st digit (which can only display '1'). |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Mon Sep 15, 2008 3:16 pm |
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| Quote: | | How to put all 4 digits on to the LCD ? |
I'm working on this problem.
I don't have the PicDem Mechatronics board, so I can't physcially test
the code. I have a question. When you run the driver and the test
program that I posted earlier in this thread, what does it display on
the LCD ? Post what you see. |
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Guest
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| Posted: Tue Sep 16, 2008 7:41 am |
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If comment out like this
setup_lcd(LCD_MUX14, 0); // | LCD_BIAS_PINS, 0);
I can compile it and "432" show on the LCD instead of "234" |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Tue Sep 16, 2008 11:13 am |
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I always thought those digits were reversed, but the person I was working
with at the time, said everything was OK. I don't have the Mechatronics
board and you can't buy the VIM-332-DP LCD (apparently), so I could
never test it in hardware.
Your version of the compiler is missing this #define statement from
the 16F917.H file. Just add the following line to the program. Put it
in the area below the #use delay() statement, where the other #define
statements are located.
| Code: | | #define LCD_BIAS_PINS 0x10 |
The code below should work better. I've corrected the reversed digits
problem and I've added support for the left-most digit ("1").
| Code: |
#include <16F917.H>
#fuses INTRC_IO, NOWDT, NOPROTECT, NOBROWNOUT, PUT
#use delay(clock=8000000)
// The LCD digits are numbered in the following way,
// according to the Varitronix VIM-332-DP data sheet.
// _ _ _
// | |_| |_| |_|
// | |_| |_| |_|
//
// Digit 4 3 2 1
//
// The CCS lcd_symbol() function will be used to display digits
// 1, 2, and 3. The following define statements tell the
// lcd_symbol() function which PIC pins are connected to the
// LCD segment pins.
// There is a table on page 58 of the PicDem Mechatronics
// Demonstration Board data sheet which lists the connections
// that are used to make these define statements.
//
// Digit segments A B C D E F G DP
// b7 b6 b5 b4 b3 b2 b1 b0
#define DIGIT3 COM0+3, COM0+11, COM2+11, COM3+3 , COM2+3, COM1+3, COM1+11, COM3+2
#define DIGIT2 COM0+6, COM0+21, COM2+21, COM3+6, COM2+6, COM1+6, COM1+21, COM3+11
#define DIGIT1 COM0+22, COM0+23, COM2+23, COM3+22, COM2+22, COM1+22, COM1+23, COM3+21
// The following array tells the CCS lcd_symbol() function which
// segments to turn on, to display the numbers from 0 to 9.
// 0 1 2 3 4 5 6 7 8 9
byte const Digit_Map[10] = {0xFC,0x60,0xDA,0xF2,0x66,0xB6,0xBE,0xE0,0xFE,0xE6};
#define BLANK 0 // For a blank digit, don't turn on any segments.
#byte LCDDATA6 = 0x116
#bit seg_4bc = LCDDATA6.2 // Controls left-most digit ("1")
int8 lcd_pos;
//-----------------------------------------------
void lcd_putc(char c)
{
int8 segments;
if(c == '\f')
{
lcd_pos = 0;
}
else
{
if((c >= '0') && (c <= '9'))
segments = Digit_Map[c - '0'];
else
segments = BLANK;
switch(lcd_pos)
{
case 1: // 1000's digit (left-most digit on lcd)
if(c == '1') // Is the top digit = 1 ?
seg_4bc = 1; // If so, display it
else // If it's not = 1, don't display it.
seg_4bc = 0;
break;
case 2: lcd_symbol(segments, DIGIT3); break; // 100's digit
case 3: lcd_symbol(segments, DIGIT2); break; // 10's digit
case 4: lcd_symbol(segments, DIGIT1); break; // 1's digit
}
}
lcd_pos++;
}
//===================================
void main()
{
int16 number;
setup_lcd(LCD_MUX14 | LCD_BIAS_PINS, 0);
number = 1234;
printf(lcd_putc,"\f%4lu",number); // Always send 4 digits
while(1);
} |
Last edited by PCM programmer on Tue Sep 16, 2008 11:33 am; edited 1 time in total |
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Guest
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| Posted: Tue Sep 16, 2008 11:28 am |
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Thanks...
It works like a champ! |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Tue Sep 16, 2008 11:36 am |
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I added a comment in my post about adding the LCD_BIAS_PINS
definition to your program. That's in there because the demo program
from Microchip (written in MPASM) has the bias pins enabled. So
supposedly they think it's necessary. |
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Guest
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| Posted: Tue Sep 16, 2008 1:04 pm |
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I try to understand the following
Can you explain how these work relate to LCD?
| Quote: | | #define DIGIT1 COM0+22, COM0+23, COM2+23, COM3+22, COM2+22, COM1+22, COM1+23, COM3+21 |
Sorry, I new to this. I try to compare your line above to the mapping worksheet that came with the demo board and still don't get it. Again what is COM0+22 and etc.? |
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