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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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 Posted: Thu Jun 15, 2006 1:12 pm |
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If you feel that you must put a delay inside an isr, and you don't
want to see that warning message, then tell the compiler to create
a 2nd instance of the delay library by adding a 2nd #use delay()
statement as shown in bold below. That way, the isr and the
code in main() (and beyond) will each have their own separate
delay routines.
| Quote: | #include <16F877.H>
#fuses XT, NOWDT, NOPROTECT, NOBROWNOUT, PUT, NOLVP
#use delay(clock = 4000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)
#int_ext
void int_ext_isr(void)
{
delay_ms(1);
}
#use delay(clock = 4000000)
//======================
void main()
{
enable_interrupts(INT_EXT);
enable_interrupts(GLOBAL);
while(1)
{
printf("Hello World\n\r");
delay_ms(100);
}
}
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grasspuddle
Joined: 15 Jun 2006
Posts: 66
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| Posted: Thu Jun 15, 2006 1:30 pm |
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i don't have a delay_ms inside the interrupt, its in a function
i have also commented out all delay_ms commands and still get the warnings
i would like to know why i still get them |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Thu Jun 15, 2006 1:35 pm |
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There must be some function that you're calling from inside the isr
and outside as well. It would help if you could post a small but
complete test program. |
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grasspuddle
Joined: 15 Jun 2006
Posts: 66
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| Posted: Thu Jun 15, 2006 2:05 pm |
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recopied all of the code into a new project and that seems to of cleared up the warnings...
it now works |
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