individual isr for each ioc pin

[x_berzerker]

hi everyone!

i'll try to be direct:
i need something like

#int_rb0
void rb0_change () { ... }

#int_rb1
void rb1_change () { ... }

but since this is not implemented (the preprocessor directives does not exists) i would like to know some hints about a better alternative for this situation.
im working on a high time precision application, so im trying to avoid checking which pin triggered the interrupt. any help would be useful.

[Ttelmah]

You have to either check the pins, or use the separate hardware interrupts (depending on the processor involved). The answer is not magic, and there is no magic solution, you need to look at the chip's data sheets, and find one that offers what you want.
A lot of the later 18F chips, have three separate interrupts, as well as the generic 'change' interrupt. However these are edge triggered in one direction, not 'change' sensitive. You can simulate a 'change' function, by reprogramming the active direction in the handler.
Seriously though, testing the pins, only involves a couple of instructions. Given that the overhead of the handler itself is typically over 50 instructions, this is minor.
Other thoughts. You can use the CCP interrupts, as two more interrupts. Again only on one edge though.

Best Wishes

[RLScott]

[x_berzerker]

i forgot to mention it. im using 16F886.
unfortunately, apparently the things cant be more direct than checking the trigger pins.